Except where otherwise noted, the contents of this document are Copyright 2010 Stuart Reges and Marty Stepp.
lab document created by Whitaker Brand and Marty Stepp
Goals for today:
for
loops to traverse and process array data
Which of the following choices is the correct syntax for declaring/initializing an array of integers?
Which of the following choices is the correct syntax for quickly declaring/initializing an array of integers to store a particular list of values?
Fill in the array with the values that would be stored after the code executes:
int[] data = new int[8]; data[0] = 3; data[7] = -18; data[4] = 5; data[1] = data[0]; int x = data[4]; data[4] = 6; data[x] = data[0] * data[1];
index | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|---|
value | 3 | 3 | 0 | 0 | 6 | 9 | 0 | -18 |
Fill in the array with the values that would be stored after the code executes:
int[] list = {2, 18, 6, -4, 5, 1}; for (int i = 0; i < list.length; i++) { list[i] = list[i] + (list[i] / list[0]); }
index | 0 | 1 | 2 | 3 | 4 | 5 |
---|---|---|---|---|---|---|
value | 3 | 24 | 8 | -5 | 6 | 1 |
Arrays
class methodsMethod name | Description |
---|---|
binarySearch(array, value)
|
returns index of value in a sorted array (< 0 if not found) |
copyOf(array, length)
|
returns a new copy of an array |
equals(array1, array2)
|
returns true if the two arrays contain same elements |
fill(array, value)
|
sets every element to the given value |
sort(array)
|
arranges the elements into sorted order |
toString(array)
|
returns a string for the array, such as "[10, 30, -25, 17]" |
double
s, and returns a new array of rounded int
s:
public static int[] roundAll(double[] realNums) { int[] roundedNums = new int[realNums.length]; for (int i = 0; i < realNums.length; i++) { roundedNums[i] = (int) Math.round(realNums[i]); } return roundedNums; }
roundAll
method from the previous slide:
import java.util.*; // to use Arrays
public class MyProgram {
public static void main(String[] args) {
double[] realNumbers = {5.5, 7.31, 8.09, -3.234234, 2.0, 0.0};
int[] roundedNumbers = roundAll(realNumbers);
System.out.println(Arrays.toString(roundedNumbers));
}
...
}
// Output: [5, 7, 8, -3, 2, 0]
Suppose that each array at right were passed as a parameter to the mystery
method below. Fill in the boxes with the array contents after each method call.
public static void mystery(int[] a) { for (int i = 0; i < a.length - 1; i++) { if (a[i] < a[i + 1]) { a[i] = a[i + 1]; } } } |
|
PromptNumbers2.java
program from a previous exercise.
public class PromptNumbers2 { public static void main(String[] args) { int count = console.nextInt(); int[] nums = new int[count]; ... System.out.println("Your numbers in forward order:"); printForward(nums); System.out.println("Your numbers in backward order:"); printBackward(nums); } // Prints the elements of the given array in forward order. public static void printForward(int[] a) { for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } // Prints the elements of the given array in backward order. public static void printBackward(int[] a) { for (int i = a.length - 1; i >= 0; i--) { System.out.println(a[i]); } } }
minGap
Write a method named minGap
that accepts an integer array as a parameter and returns the minimum 'gap' between adjacent values in the array. The gap between two adjacent values in a array is defined as the second value minus the first value. For example, suppose a variable called array
is an array of integers that stores the following sequence of values:
int[] array = {1, 3, 6, 7, 12};
The first gap is 2 (3 - 1), the second gap is 3 (6 - 3), the third gap is 1 (7 - 6) and the fourth gap is 5 (12 - 7). Thus, the call of minGap(array)
should return 1
because that is the smallest gap in the array. If you are passed an array with fewer than 2 elements, you should return 0
.
Click on the check-mark above to try out your solution in Practice-it!
percentEven
Write a method named percentEven
that accepts an array of integers as a parameter and returns the percentage of even numbers in the array as a real number. For example, if a variable named nums
refers to an array of the elements {6, 2, 9, 11, 3}
, then the call of percentEven(nums)
should return 40.0
. If the array contains no even elements or no elements at all, return 0.0
.
Click on the check-mark above to try out your solution in Practice-it!
What values are stored in the array at the comment in main? Note that the incrementAll
returns void, but does take an int[]
parameter.
public class ArrayReference {
public static void main(String[] args) {
int[] nums = {2, 4, -1, 3};
incrementAll(nums);
// HERE!
}
public static void incrementAll(int[] data) {
for (int i = 0; i < data.length; i++) {
data[i]++;
}
}
}
index | 0 | 1 | 2 | 3 |
---|---|---|---|---|
value | 3 | 5 | 0 | 4 |
swapAll
Write a method named swapAll
that accepts two arrays of integers as parameters and swaps their entire contents. You may assume that the arrays passed are not null and are the same length.
For example, if the following arrays are passed:
int[] a1 = {11, 42, -5, 27, 0, 89}; int[] a2 = {10, 20, 30, 40, 50, 60}; swapAll(a1, a2);
After the call, the arrays should store the following elements:
a1: {10, 20, 30, 40, 50, 60} a2: {11, 42, -5, 27, 0, 89}
stretch
Write a method named stretch
that accepts an array of integers as a parameter and returns a new array twice as large as the original, replacing every integer from the original array with a pair of integers, each half the original. If a number in the original array is odd, then the first number in the new pair should be one higher than the second so that the sum equals the original number. For example, if a variable named list
refers to an array storing the values {18, 7, 4, 24, 11}
, the call of stretch(list)
should return a new array containing {9, 9, 4, 3, 2, 2, 12, 12, 6, 5}
. (The number 18 is stretched into the pair 9, 9, the number 7 is stretched into 4, 3, the number 4 is stretched into 2, 2, the number 24 is stretched into 12, 12 and the number 11 is stretched into 6, 5.)
Click on the check-mark above to try out your solution in Practice-it!
1 2 3 4 5 6 7 8 9 10 |
// Returns the largest value in the given array.
public static int max(int data[10]) {
int max = 0;
for (int i = 0; i < data[].length(); i++) {
if (array[i] > max) {
max = array[i];
}
}
return max[];
}
|
The above attempted solution to Practice-It problem "max
" has 7 problems.
Open Practice-It from the link above, copy/paste this code into it, and fix the errors. Complete the code so that it passes the test cases.
[10]
after parameter name; should write []
(without length) after int
max
at 0
won't work if the array is all negative. Should initialize max
variable to be data[0]
and start for
loop at index 1
[]
after data
here
()
after length
here
array
should be data
array
should be data
[]
after max
here
1 2 3 4 5 6 7 8 9 10 |
// Returns the largest value in the given array. public static int max(int[] data) { int max = data[0]; for (int i = 1; i < data.length; i++) { if (data[i] > max) { max = data[i]; } } return max; } |
If you finish all the exercises, try out our Practice-It web tool. It lets you solve Java problems from our Building Java Programs textbook.
You can view an exercise, type a solution, and submit it to see if you have solved it correctly.
Choose some problems from Chapter 7 and try to solve them!