Except where otherwise noted, the contents of this document are Copyright 2013 Stuart Reges and Marty Stepp.
lab document created by Marty Stepp, Stuart Reges and Whitaker Brand
Goals for this problem set:
Which of the following choices is the correct syntax for declaring/initializing an array of integers?
Which of the following choices is the correct syntax for quickly declaring/initializing an array of integers to store a particular list of values? We didn't get to this in lecture -- check the slides or chapter 7 in the book.
Fill in the array with the values that would be stored after the code executes:
int[] data = new int[8]; data[0] = 3; data[7] = -18; data[4] = 5; data[1] = data[0]; int x = data[4]; data[4] = 6; data[x] = data[0] * data[1];
index | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|---|
value | 3 | 3 | 0 | 0 | 6 | 9 | 0 | -18 |
Fill in the array with the values that would be stored after the code executes:
int[] list = {2, 18, 6, -4, 5, 1}; for (int i = 0; i < list.length; i++) { list[i] = list[i] + (list[i] / list[0]); }
index | 0 | 1 | 2 | 3 | 4 | 5 |
---|---|---|---|---|---|---|
value | 3 | 24 | 8 | -5 | 6 | 1 |
public static type name(type[] name) { // pass array parameter
public static type[] name(parameters) { // return array
double
s, and returns a new array of rounded int
s:
public static int[] roundAll(double[] realNums) { int[] roundedNums = new int[realNums.length]; for (int i = 0; i < realNums.length; i++) { roundedNums[i] = (int) Math.round(realNums[i]); } return roundedNums; }
roundAll
method from the previous slide:
import java.util.*; // to use Arrays
public class MyProgram {
public static void main(String[] args) {
double[] realNumbers = {5.5, 7.31, 8.09, -3.234234, 2.0, 0.0};
int[] roundedNumbers = roundAll(realNumbers);
System.out.println(Arrays.toString(roundedNumbers));
}
...
}
// Output: [5, 7, 8, -3, 2, 0]
Arrays
class methodsMethod name | Description |
---|---|
Arrays.binarySearch(array, value)
|
returns index of value in a sorted array (< 0 if not found) |
Arrays.copyOf(array, length)
|
returns a new copy of an array |
Arrays.equals(array1, array2)
|
returns true if the two arrays contain same elements |
Arrays.fill(array, value)
|
sets every element to the given value |
Arrays.sort(array)
|
arranges the elements into sorted order |
Arrays.toString(array)
|
returns a string for the array, such as "[10, 30, -25, 17]" |
What values are stored in the array at the comment in main
?
Note that the incrementAll
method returns void
, but does take an int[]
parameter.
public class ArrayReference {
public static void main(String[] args) {
int[] nums = {2, 4, -1, 3};
incrementAll(nums);
// HERE!
}
public static void incrementAll(int[] data) {
for (int i = 0; i < data.length; i++) {
data[i]++;
}
}
}
index | 0 | 1 | 2 | 3 |
---|---|---|---|---|
value | 3 | 5 | 0 | 4 |
Solve another reference mystery problem on PracticeIt!
Discuss it with your neighbor before submitting the answer and make sure you agree with each other's solution. There will be a problem of this type on the final!
Suppose that each array at right were passed as a parameter to
the mystery
method below. Fill in the boxes with the array
contents after each method call.
public static void mystery(int[] a) { for (int i = 0; i < a.length - 1; i++) { if (a[i] < a[i + 1]) { a[i] = a[i + 1]; } } } |
|
3 | 28 | 53 | 78 |
continued on the next slide...
System.out.print
inside the if
on line 23 and debug the program.
count
,
and drop it on the main code window. This will show a view of its contents. count
array?
index | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|---|
value | 4 | 4 | 0 | 10 | 0 | 4 | 4 | 0 |
continued on the next slide...
System.out.print
is about to execute, then stops.)
index | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|---|
value | 8 | 8 | 0 | 20 | 0 | 8 | 8 | 0 |
index | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 |
---|---|---|---|---|---|---|---|---|
value | 0 | 0 | 0 | 8 | 8 | 0 | 0 | 0 |
1 2 3 4 5 6 7 8 9 10 |
// Returns the largest value in the given array.
public static int max(int data[10]) {
int max = 0;
for (int i = 0; i < data[].length(); i++) {
if (array[i] > max) {
max = array[i];
}
}
return max[];
}
|
The above attempted solution to Practice-It problem "max
" has
7 problems. Open Practice-It from the link above, copy/paste this code
into it, and fix the errors. Complete the code so that it passes the test
cases.
[10]
after parameter name; should
write []
(without length) after int
max
at 0
won't work if the
array is all negative. Should initialize max
variable to
be data[0]
and start for
loop at
index 1
[]
after data
here
()
after length
here
array
should be data
array
should be data
[]
after max
here
1 2 3 4 5 6 7 8 9 10 |
// Returns the largest value in the given array. public static int max(int[] data) { int max = data[0]; for (int i = 1; i < data.length; i++) { if (data[i] > max) { max = data[i]; } } return max; } |
PromptNumbers.java
program from a previous exercise.
public class PromptNumbers2 { public static void main(String[] args) { int count = console.nextInt(); int[] nums = new int[count]; ... System.out.println("Your numbers in forward order:"); printForward(nums); System.out.println("Your numbers in backward order:"); printBackward(nums); } // Prints the elements of the given array in forward order. public static void printForward(int[] a) { for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } } // Prints the elements of the given array in backward order. public static void printBackward(int[] a) { for (int i = a.length - 1; i >= 0; i--) { System.out.println(a[i]); } } }
minGap
Write a method named minGap
that accepts an integer array as a
parameter and returns the minimum 'gap' between adjacent values in the
array. The gap between two adjacent values in a array is defined as the
second value minus the first value. For example, suppose a variable
called array
is an array of integers that stores the following
sequence of values:
int[] array = {1, 3, 6, 7, 12};
The first gap is 2 (3 - 1), the second gap is 3 (6 - 3), the third gap is 1
(7 - 6) and the fourth gap is 5 (12 - 7). Thus, the call
of minGap(array)
should return 1
because that is
the smallest gap in the array. If you are passed an array with fewer than
2 elements, you should return 0
.
Click on the check-mark above to try out your solution in Practice-it!
percentEven
Write a method named percentEven
that accepts an array of
integers as a parameter and returns the percentage of even numbers in the
array as a real number. For example, if a variable named nums
refers to an array of the elements {6, 2, 9, 11, 3}
, then the
call of percentEven(nums)
should return 40.0
. If
the array contains no even elements or no elements at all,
return 0.0
.
Click on the check-mark above to try out your solution in Practice-it!
copyRange
Write a method named copyRange
that takes as parameters two
arrays a1
and a2
, two starting
indexes i1
and i2
, and a length l
,
and copies the first l
elements of a1
starting at
index i1
into array a2
starting at
index i2
.
For example, if the following arrays are declared:
int[] a1 = {10, 20, 30, 40, 50, 60}; int[] a2 = {91, 92, 93, 94, 95, 96}; copyRange(a1, a2, 0, 2, 3);
After the preceding call, the contents of a2
would
be {91, 92, 10, 20, 30, 96}
. You may assume that the
parameters' values are valid, that the arrays are large enough to hold the
data, and so on.
equals
Write a method named equals
that accepts two arrays of integers as parameters and returns true
if they contain exactly the same elements in the same order, and false
otherwise.
Note that the arrays might not be the same length; if the lengths differ, return false
. Do not call Arrays.equals
in your solution.
For example, if the following arrays are declared:
int[] a1 = {10, 20, 30, 40, 50, 60}; int[] a2 = {10, 20, 30, 40, 50, 60}; int[] a3 = {20, 3, 50, 10, 68};
The call equals(a1, a2)
returns true
but the call equals(a1, a3)
returns false
.
append
Write a method called append
that accepts two integer arrays as parameters and that returns a new array that contains the result of appending the second array's values at the end of the first array.
You should solve this problem in Practice-It!
swapAll
Write a method named swapAll
that accepts two arrays of
integers as parameters and swaps their entire contents. You may assume that
the arrays passed are not null and are the same length.
For example, if the following arrays are passed:
int[] a1 = {11, 42, -5, 27, 0, 89}; int[] a2 = {10, 20, 30, 40, 50, 60}; swapAll(a1, a2);
After the call, the arrays should store the following elements:
a1: {10, 20, 30, 40, 50, 60} a2: {11, 42, -5, 27, 0, 89}